Some compilers will allow it when they are run in certain ways, but it is invalid c. For this, the best way (and the most common way) is to use the c_str () member function,. I defined bf as the type of an array of 5 chars, then tried 5 different ways to declare and initialize objects of that type:
Scanf(%s,&a[100]) is wrong, &a[100] is the address of the 101st char in your array, you want the address of the first character, so it should be &a[0] or simply a. To do that, you need to pass it to ini as a parameter. As unholysheep has written you must initialize and not only declare the variable nand_loadtable_d:
Using std::array might be a. You're trying to dynamically initialize tablica in main by calling ini. El error viene a decir que. First, it ensures that the array is initialized with the correct number of elements.
Las formaciones 1 deben inicializarse con un inicializador entre llaves. Int cipher[array_size][array_size]= { { 0 } }; I think color_to_565 () is not a constant (even though it's an inline function), so it can't be used to initialize a global static variable. A couple of obvious things:
Conflicting declaration 'int lfsensor [1]' int. Try defining it as another macro, instead. To fix the 'array must be initialized with a brace enclosed initializer' error message, check the array initialization syntax, check for missing or extra braces, check for typing errors, and check. You return a locally declared.
The syntax to statically initialize an array uses curly braces, like this: First, an array cannot have size 0. A special kind of initialization for char arrays works. For example, the following code initializes an array of strings.